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描述:给定链表 head,对于每个节点,查找其右侧第一个值严格大于它的节点。返回整数数组 answer,answer[i] 为第 i 个节点的下一个更大节点值;若无,则为 0。
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(三)在当地有常住户口和固定住所;
But those tricks, I believe, are quite clear to everybody that has worked extensively with automatic programming in the latest months. To think in terms of “what a human would need” is often the best bet, plus a few LLMs specific things, like the forgetting issue after context compaction, the continuous ability to verify it is on the right track, and so forth.